CBSE  /  Class 10  /  Maths  /  Coordinate Geometry

  • 1. 
    The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2, 3), B(6, 7) and C(8, 3) is

  • (0, 1)
  • (0, -1)
  • (-1, 0)
  • (1, 0)

  • 2. 
    If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then

  • AP = \(\frac{1}{3}\) AB
  • AP = PB
  • PB = \(\frac{1}{3}\) AB
  • AP = \(\frac{1}{2}\) AB

  • 3. 
    If P (\(\frac{α}{3}\), 4) is the mid-point of the line segment joining the points Q(-6, 5) and R(-2, 3), then the value of‘a’ is

  • -4
  • -12
  • 12
  • -6

  • 4. 
    The perpendicular bisector of the line segment joining the points A(l, 5) and B(4, 6) cuts the y-axis at

  • (0, 13)
  • (0, -13)
  • (0, 12)
  • (13, 0)

  • 5. 
    The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure.

  • (x, y)
  • (y, x)
  • (\(\frac{x}{2}\), \(\frac{y}{2}\))
  • (\(\frac{y}{2}\), \(\frac{x}{2}\))

  • 6. 
    A circle drawn with origin as the centre passes through ([latex]\frac{13}{2}[/latex], 0). The point which does not lie in the interior of the circle is

  • (-\(\frac{3}{4}\), 1)
  • (2, \(\frac{7}{3}\))
  • (5, -\(\frac{1}{2}\))
  • (-6, \(\frac{5}{2}\))

  • 7. 
    A line intersects the y-axis and x-axis at the points P and Q respectively. If (2, -5) is the mid-point of PQ, then the coordinates of P and Q are respectively

  • (0, -5) and (2, 0)
  • (0, 10) and (-4, 0)
  • (0, 4) and (-10, 0)
  • (0, -10) and (4, 0)

  • 8. 
    area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is

  • (a + b + c)²
  • 0
  • a + b + c
  • abc

  • 9. 
    If the distance between the points (4, P) and (1, 0) is 5, then the value of P is

  • 4 only
  • ± 4
  • -4 only
  • 0

  • 10. 
    If the points A(1, 2), O(0, 0), C(a, b) are collinear, then

  • a = b
  • a = 2b
  • 2a = b
  • a = -b
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