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MCQ Questions for CBSE Class 12 with Answers
MCQ Questions for CBSE Class 11 with Answers
MCQ Questions for CBSE Class 10 with Answers
MCQ Questions for CBSE Class 9 with Answers
MCQ Questions for CBSE Class 8 with Answers
MCQ Questions for CBSE Class 7 with Answers
MCQ Questions for CBSE Class 6 with Answers
MCQ Questions for CBSE Class 5 with Answers
MCQ Questions for CBSE Class 4 with Answers
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MCQ Questions for CBSE Class 1 with Answers
Quiz
CBSE
/
Class 12
/
Maths
/
Continuity and Differentiability
1.
If f (x) = 2x and g (x) = \(\frac{x^2}{2}\) + 1, then’which of the following can be a discontinuous function
f(x) + g(x)
f(x) – g(x)
f(x).g(x)
\(\frac{g(x)}{f(x)}\)
2.
The function f(x) = \(\frac{4-x^2}{4x-x^3}\) is
discontinuous at only one point at x = 0
discontinuous at exactly two points
discontinuous at exactly three points
None of these
3.
The set of points where the function f given by f (x) =| 2x – 1| sin x is differentiable is
R
R = {\(\frac{1}{2}\)}
(0, ∞)
None of these
4.
The function f(x) = cot x is discontinuous on the set
{x = nπ, n ∈ Z}
{x = 2nπ, n ∈ Z}
{x = (2n + 1) \(\frac{π}{2}\) n ∈ Z}
{x – \(\frac{nπ}{2}\) n ∈ Z}
5.
The function f(x) = e is
continuous everywhere but not differentiable at x = 0
continuous and differentiable everywhere
not continuous at x = 0
None of these
6.
If f(x) = x² sin\(\frac{1}{x}\), where x ≠ 0, then the value of the function f(x) at x = 0, so that the function is continuous at x = 0 is
0
-1
1
None of these
7.
If f(x) = is continuous at x = \(\frac{π}{2}\), then
m = 1, n = 0
m = \(\frac{nπ}{2}\) + 1
n = \(\frac{mπ}{2}\)
m = n = \(\frac{π}{2}\)
8.
If y = log(\(\frac{1-x^2}{1+x^2}\)), then \(\frac{dy}{dx}\) is equal to
\(\frac{4x^3}{1-x^4}\)
\(\frac{-4x}{1-x^4}\)
\(\frac{1}{4-x^4}\)
\(\frac{-4x^3}{1-x^4}\)
9.
Let f(x) = |sin x| Then
f is everywhere differentiable
f is everywhere continuous but not differentiable at x = nπ, n ∈ Z
f is everywhere continuous but no differentiable at x = (2n + 1) \(\frac{π}{2}\) n ∈ Z
None of these
10.
If y = \(\sqrt{sin x+y}\) then \(\frac{dy}{dx}\) is equal to
\(\frac{cosx}{2y-1}\)
\(\frac{cosx}{1-2y}\)
\(\frac{sinx}{1-xy}\)
\(\frac{sinx}{2y-1}\)
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