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MCQ Questions for CBSE Class 12 with Answers
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MCQ Questions for CBSE Class 9 with Answers
MCQ Questions for CBSE Class 8 with Answers
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Quiz
CBSE
/
Class 12
/
Maths
/
Vector Algebra
1.
If \(\vec{a}\) and \(\vec{b}\) are any two vector then (\(\vec{a}\) × \(\vec{b}\))² is equal to
(\(\vec{a}\))²(\(\vec{b}\))² – (\(\vec{a}\).\(\vec{b}\))²
(\(\vec{a}\))² (\(\vec{b}\))² + (\(\vec{a}\).\(\vec{b}\))²
(\(\vec{a}\).\(\vec{b}\))²
(\(\vec{a}\))²(\(\vec{b}\))²
2.
If \(\hat{a}\) and \(\hat{b}\) be two unit vectors and 0 is the angle between them, then |\(\hat{a}\) – \(\hat{b}\)| is equal to
sin \(\frac{θ}{2}\)
2 sin \(\frac{θ}{2}\)
cos \(\frac{θ}{2}\)
2 cos \(\frac{θ}{2}\)
3.
The angle between the vector 2\(\hat{i}\) + 3\(\hat{j}\) + \(\hat{k}\) and 2\(\hat{i}\) – \(\hat{j}\) – \(\hat{k}\) is
\(\frac{π}{2}\)
\(\frac{π}{4}\)
\(\frac{π}{3}\)
0
4.
If \(\vec{a}\) = \(\hat{i}\) – \(\hat{j}\) + \(\hat{k}\), \(\vec{b}\) = \(\hat{i}\) + 2\(\hat{j}\) – \(\hat{k}\), \(\vec{c}\) = 3\(\hat{i}\) – p\(\hat{j}\) – 5\(\hat{k}\) are coplanar then P =
6
-6
2
-2
5.
The distance of the point (- 3, 4, 5) from the origin
50
5√2
6
None of these
6.
If \(\vec{AB}\) = 2\(\hat{i}\) + \(\hat{j}\) – 3\(\hat{k}\) and the co-ordinates of A are (1, 2, -1) then coordinate of B are
(2, 2, -3)
(3, 2, -4)
(4, 2, -1)
(3, 3, -4)
7.
If \(\vec{b}\) is a unit vector in xy-plane making an angle of \(\frac{π}{4}\) with x-axis. then \(\vec{b}\) is equal to
\(\hat{i}\) + \(\hat{j}\)
\(\vec{i}\) – \(\vec{j}\)
\(\frac{\vec{i}+\vec{j}}{√2}\)
\(\frac{\vec{i}-\vec{j}}{√2}\)
8.
\(\vec{a}\) = 2\(\hat{i}\) + \(\hat{j}\) – 8\(\hat{k}\) and \(\vec{b}\) = \(\hat{i}\) + 3\(\hat{j}\) – 4\(\hat{k}\) then the magnitude of \(\vec{a}\) + \(\vec{b}\) is equal to
13
\(\frac{13}{4}\)
\(\frac{3}{13}\)
\(\frac{4}{13}\)
9.
The vector in the direction of the vector \(\hat{i}\) – 2\(\hat{j}\) + 2\(\hat{k}\) that has magnitude 9 is
\(\hat{i}\) – 2\(\hat{j}\) + 2\(\hat{k}\)
\(\frac{\hat{i}-2\hat{j}+2\hat{k}}{3}\)
3(\(\hat{i}\) – 2\(\hat{j}\) + 2\(\hat{k}\))
9(\(\hat{i}\) – 2\(\hat{j}\) + 2\(\hat{k}\))
10.
The position vector of the point which divides the join of points 2\(\vec{a}\) – 3\(\vec{b}\) and \(\vec{a}\) + \(\vec{b}\) in the ratio 3 : 1 is
\(\frac{3\vec{a}-2\vec{b}}{2}\)
\(\frac{7\vec{a}-8\vec{b}}{2}\)
\(\frac{3\vec{a}}{2}\)
\(\frac{5\vec{a}}{4}\)
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