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MCQ Questions for CBSE Class 12 with Answers
MCQ Questions for CBSE Class 11 with Answers
MCQ Questions for CBSE Class 10 with Answers
MCQ Questions for CBSE Class 9 with Answers
MCQ Questions for CBSE Class 8 with Answers
MCQ Questions for CBSE Class 7 with Answers
MCQ Questions for CBSE Class 6 with Answers
MCQ Questions for CBSE Class 5 with Answers
MCQ Questions for CBSE Class 4 with Answers
MCQ Questions for CBSE Class 3 with Answers
MCQ Questions for CBSE Class 2 with Answers
MCQ Questions for CBSE Class 1 with Answers
Quiz
CBSE
/
Class 12
/
Maths
/
Vector Algebra
1.
If |\(\vec{a}\)| 4 and – 3 ≤ λ ≤ 2, then the range of |λ\(\vec{a}\)| is
[0, 8]
[-12, 8]
[0, 12]
[8, 12]
2.
The number of vectors of unit length perpendicular to the vectors \(\vec{a}\) = 2\(\hat{i}\) + \(\hat{j}\) + 2\(\hat{k}\) and \(\vec{b}\) = \(\hat{j}\) + \(\hat{k}\) is
one
two
three
infinite
3.
If (\(\frac{1}{2}\), \(\frac{1}{3}\), n) are the direction cosines of a line, then the value of n is
\(\frac{\sqrt{23}}{6}\)
\(\frac{23}{6}\)
\(\frac{2}{3}\)
–\(\frac{3}{2}\)
4.
Find the magnitude of vector 3\(\hat{i}\) + 2\(\hat{j}\) + 12\(\hat{k}\)
\(\sqrt{157}\)
4\(\sqrt{11}\)
\(\sqrt{213}\)
9√3
5.
Three points (2, -1, 3), (3, – 5, 1) and (-1, 11, 9) are
Non-collinear
Non-coplanar
Collinear
None of these
6.
The vectors 3\(\hat{i}\) + 5\(\hat{j}\) + 2\(\hat{k}\), 2\(\hat{i}\) – 3\(\hat{j}\) – 5\(\hat{k}\) and 5\(\hat{i}\) + 2\(\hat{j}\) – 3\(\hat{k}\) form the sides of
Isosceles triangle
Right triangle
Scalene triangle
Equilateral triangle
7.
The points with position vectors 60\(\hat{i}\) + 3\(\hat{j}\), 40\(\hat{i}\) – 8\(\hat{j}\) and a\(\hat{i}\) – 52\(\hat{j}\) are collinear if
a = -40
a = 40
a = 20
None of these
8.
The ratio in which 2x + 3y + 5z = 1 divides the line joining the points (1, 0, -3) and (1, -5, 7) is
5 : 3
3 : 2
2 : 1
1 : 3
9.
If O is origin and C is the mid point of A (2, -1) and B (-4, 3) then the value of \(\bar{OC}\) is
\(\hat{i}\) + \(\hat{j}\)
\(\hat{i}\) – \(\hat{j}\)
–\(\hat{i}\) + \(\hat{j}\)
–\(\hat{i}\) – \(\hat{j}\)
10.
If ABCDEF is regular hexagon, then \(\vec{AD}\) + \(\vec{EB}\) + \(\vec{FC}\) is equal
0
2\(\vec{AB}\)
3\(\vec{AB}\)
4\(\vec{AB}\)
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