CBSE  /  Class 12  /  Physics  /  Moving Charges and Magnetism

  • 1. 
    What happens to the magnetic field at the centre of a circular current carrying coil if we double the radius of the coil keeping the current unchanged?

  • halved
  • doubled
  • quadrupled
  • remains unchanged

  • 2. 
    When we double the radius of a coil keeping the current through it unchanged, what happens to the magnetic field directed along its axis at far off points?

  • halved
  • doubled
  • quadrupled
  • remains unchanged

  • 3. 
    The strength of the magnetic field around an infinite current carrying conductor is :

  • same everywhere
  • inversely proportional to the distance
  • directly proportional to the distance
  • None of these

  • 4. 
    A current carrying power line carries current from west to east. Then the direction of the magnetic field 2 m above it is :

  • west to east
  • south to north
  • north to south
  • None of these

  • 5. 
    The force between two parallel current carrying conductors is F. If the current in each conductor is doubled, then the force between them becomes :

  • 4F
  • 2F
  • F
  • \(\frac{F}{4}\)

  • 6. 
    How much force will be experienced by a moving charge in a magnetic field? The symbols have their usual meanings.

  • \(\vec{F}\) = q(\(\vec{v}\).\(\vec{B}\))
  • \(\vec{F}\) = \(\frac{q}{(\vec{v}.\vec{B})}\)
  • \(\vec{F}\) = \(\frac{q}{2}\)\((\vec{v}×\vec{B}\))
  • \(\vec{F}\) = q(\(\vec{v}\)×\(\vec{B}\))

  • 7. 
    Which of the following is not a unit of magnetic induction?

  • gauss
  • tesla
  • oersted
  • weber/metre²

  • 8. 
    The magnetic field produced by an / meter long straight (x cry thin) current (I) carry ing conductor at any point on itself is :

  • zero
  • infinite
  • \(\frac{µ_0l}{4πl}\)
  • \(\frac{µ_0l}{2πl}\)

  • 9. 
    A charge + q is sent through a magnetic field. The force acting on it is maximum w hen the angle between the direction of motion of the charged particle and the magnetic field :

  • 0°
  • 45°
  • 90°
  • 180°

  • 10. 
    An electron having mass 'm' and Kinetic energy E enters in uniform magnetic field B perpendicular, then its frequency will be:

  • \(\frac{eE}{qmB}\)
  • \(\frac{2πm}{eB}\)
  • \(\frac{eB}{2πm}\)
  • \(\frac{2m}{eBE}\)
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