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Oscillation MCQ For Neet
1.
The time period of a simple pendulum is T remaining at rest inside a lift. Find the time period of the pendulum when the lift starts to move up with an acceleration of g/3
T
T/2
2T/5
T√3/2
2.
The displacement of a particle performing simple harmonic motion is given by,x= 8 sin ωt + 6 cos ωt, where distance is in cm and time is in second. The amplitude of motion is
36 m
1m
1/36 m
⅙ m
3.
A particle executes S.H.M of amplitude A. At what distance from the mean position is its kinetic energy equal to its potential energy?
10 cm
14 cm
2 cm
3.5 cm
4.
A simple pendulum on length l and mass m is suspended vertically. The string makes an angle θ with the vertical. The restoring force acting on the pendulum is
0.51 A
0.61 A
0.71 A
0.81 A
5.
The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (if it is a second’s pendulum on earth)
mg tanθ
mg sinθ
– mg sinθ
– mg cosθ
6.
A particle of mass m is hanging vertically by an ideal spring of force constant k. If the mass is made to oscillate vertically, its total energy is
1/√2 second
2 x √2 second
2 second
½ second
7.
For a magnet of a time period T magnetic moment is M. If the magnetic moment becomes one-fourth of the initial value, then the time period of oscillation becomes
Maximum at extreme position
Maximum at mean position
Minimum at mean position
Same at all positions
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