• 1. 
    The time period of a simple pendulum is T remaining at rest inside a lift. Find the time period of the pendulum when the lift starts to move up with an acceleration of g/3

  • T
  • T/2
  • 2T/5
  • T√3/2
  • 2. 
    The displacement of a particle performing simple harmonic motion is given by,x= 8 sin ωt + 6 cos ωt, where distance is in cm and time is in second. The amplitude of motion is

  • 36 m
  • 1m
  • 1/36 m
  • ⅙ m
  • 3. 
    A particle executes S.H.M of amplitude A. At what distance from the mean position is its kinetic energy equal to its potential energy?

  • 10 cm
  • 14 cm
  • 2 cm
  • 3.5 cm
  • 4. 
    A simple pendulum on length l and mass m is suspended vertically. The string makes an angle θ with the vertical. The restoring force acting on the pendulum is

  • 0.51 A
  • 0.61 A
  • 0.71 A
  • 0.81 A
  • 5. 
    The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (if it is a second’s pendulum on earth)

  • mg tanθ
  • mg sinθ
  • – mg sinθ
  • – mg cosθ
  • 6. 
    A particle of mass m is hanging vertically by an ideal spring of force constant k. If the mass is made to oscillate vertically, its total energy is

  • 1/√2 second
  • 2 x √2 second
  • 2 second
  • ½ second
  • 7. 
    For a magnet of a time period T magnetic moment is M. If the magnetic moment becomes one-fourth of the initial value, then the time period of oscillation becomes

  • Maximum at extreme position
  • Maximum at mean position
  • Minimum at mean position
  • Same at all positions
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