CBSE  /  Class 10  /  Maths  /  Triangles

  • 1. 
    In the given figure, ΔACB ~ ΔAPQ. If AB = 6 cm, BC = 8 cm, and PQ = 4 cm then AQ is equal to

  • 2 cm
  • 2.5 cm
  • 3 cm
  • 3.5 cm

  • 2. 
    ΔDEF ~ ΔABC. If DE : AB = 2 : 3 and ar ΔDEF is equal to 44 square units then ar (ΔABC) (square unit) is

  • 99
  • 120
  • [latex]\frac{176}{9}[/latex]
  • 66

  • 3. 
    ΔABC and ΔBDE are two equilateral triangles such that D is the mid point of BC. Ratio of the areas of triangle ΔABC and ΔBDE is.

  • 2 : 1
  • 1 : 2
  • 4 : 1
  • 1 : 4

  • 4. 
    If ΔABC ~ ΔPQR, \(\frac{ar ΔABC}{ar ΔPQR}\) = \(frac{9}{4}\) and AB = 18 cm, then the length of PQ is

  • 14 cm
  • 8 cm
  • 10 cm
  • 12 cm

  • 5. 
    In the given figure ΔABC ~ ΔPQR, PM is median of ΔPQR. If ar ΔABC = 289 cm², BC = 17 cm, MR = 6.5 cm then the area of ΔPQM is

  • 169 cm²
  • 13 cm²
  • 84.5 cm²
  • 144.5 cm²

  • 6. 
    If the ratio of the perimeters of two similar triangles is 4 : 25, then the ratio of the areas of the similar triangles is

  • 16 : 625
  • 2 : 5
  • 5 : 2
  • 625 : 16

  • 7. 
    In the given figure, PQ = 24 cm, QR = 26 cm ∠PAR = 90°, PA = 6 cm, and AR = 8 cm, the degree measure of ∠QPR is

  • 90°
  • 100°
  • 50°
  • 45°

  • 8. 
    In the given figure the value of x is

  • 4 cm
  • 5 cm
  • 8 cm
  • 3 cm

  • 9. 
    ΔPQR is an equilateral triangle with each side of length 2p. If PS ⊥ QR, then PS is equal to

  • \(\frac{√3}{2}\)p
  • 2p
  • √3p
  • p

  • 10. 
    In ΔLMN, ∠L = 50° and ∠N = 60°, If ΔLMN ~ ΔPQR, then find ∠Q

  • 50°
  • 70°
  • 60°
  • 40°
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